Angular rotation
The drill used by the most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 rpm. These drills, along with ultrasonic dental drills, are the fastest turbines in the world-far exceeding the angular speeds of jet engines. Suppose a drill starts at rest and comes up to operating speed in 2.0 s. Part A: Find the angular acceleration produced by the drill, assuming it to be constant. Express your answer using two significant figures Step 1: ω = 350000 rpm (revolution per minute), but in SI unit is rad/s so we have to convert to rad/s. 1 rev = 2 π rad 1 min = 60 s So we get ω = (350000 rev)*( 2 π rad/rev)*(1/60 s/m) =36651.9 rad/s Step 2: the drill starts at a rest so we get initial angular speed: ω0 = 0 rad/s Time to exceed the angular speeds of jet engines: Δt = 2 s what is angular acceleration: α = ? Step 3: ω = ω0 + α*t <=> ω = α*t => α =...