Physics

The drill used by the most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 rpm. These drills, along with ultrasonic dental drills, are the fastest turbines in the world-far exceeding the angular speeds of jet engines. Suppose a drill starts at rest and comes up to operating speed in 2.0 s. Part A: Find the angular acceleration produced by the drill, assuming it to be constant.   Express your answer using two significant figures Step 1:  ω = 350000 rpm (revolution per minute), but in SI unit is rad/s so we have to convert to rad/s.  1 rev = 2 π rad 1 min = 60 s So we get  ω =  (350000 rev)*(  2 π rad/rev)*(1/60 s/m) =36651.9 rad/s Step 2: the drill starts at a rest so we get initial angular speed:  ω0 = 0 rad/s Time to exceed the angular speeds of jet engines: Δt = 2 s what is angular acceleration: α = ? Step 3: ω =  ω0 +  α*t <=>  ω =   α*t =>  α =...

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Hi everyone, Thanks for visiting my blog. My name is An Lam. I am a student from Lone Star Cy-fair college (" http://www.lonestar.edu/cyfair.htm ") I really love physics. I know you guys love it too. Right? I am currently taking physics 1401. While my classmates and I doing homework, there are some problems that people from others group, or class doesn't know how to solve it. My blog will concentrate on what currently studying in Lone Star right now. I hope it will help you and me understand 100% what we are studying. Enjoy, Thanks!